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Popular Geometry >

axis 81x^2-1296x+16y^2+64y=-3952

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Solution

axis

Solution

semi−majoraxisb=9,semi−minoraxisa=4
Solution steps
81x2−1296x+16y2+64y=−3952
Rewrite 81x2−1296x+16y2+64y=−3952in the form of the standard ellipse equation
42(x−8)2​+92(y−(−2))2​=1
Therefore ellipse properties are:(h,k)=(8,−2),a=4,b=9
b>atherefore bis semi-major axis and ais semi-minor axisEllipsewithcenter(h,k)=(8,−2),b=9,a=4

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Frequently Asked Questions (FAQ)

  • What is the axis 81x^2-1296x+16y^2+64y=-3952 ?

    The axis 81x^2-1296x+16y^2+64y=-3952 is semi-major axis b=9, semi-minor axis a=4
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