What is the axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 ?

The axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 is semi-major axis a=7, semi-minor axis b=3

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axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1

axis

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

semi - major axis a = 7, semi - minor axis b = 3

Solution steps

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 8 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 8 ) ^{2}}{7 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (8, - 5), a = 7, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (8, - 5), a = 7, b = 3

\frac{( x - 3 ) ^{2}}{5} + \frac{( y - 1 ) ^{2}}{15} = 1

9 X^{2} + 4 Y^{2} = 36

25 x^{2} - 200 x + y^{2} + 4 y + 379 = 0

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 9 ) ^{2}}{25} = 1

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0

What is the axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 ?
The axis ((x-8)^2}{49}+\frac{(y+5)^2)/9 =1 is semi-major axis a=7, semi-minor axis b=3