What is the eccentricity (x^2)/(49)+(y^2)/(25)=1 ?

The eccentricity (x^2)/(49)+(y^2)/(25)=1 is (2sqrt(6))/7

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eccentricity (x^2)/(49)+(y^2)/(25)=1

eccentricity

\frac{x ^{2}}{49} + \frac{y ^{2}}{25} = 1

\frac{2 6}{7}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{49} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 5

= \frac{7 ^{2} - 5 ^{2}}{7}

\frac{7 ^{2} - 5 ^{2}}{7} = \frac{2 6}{7}

= \frac{2 6}{7}

x^{2} + \frac{y ^{2}}{4} = 1

x^{2} + 4 y^{2} = 46

+ x^{2} = 4 y - 2 y^{2}

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1

36 x^{2} + 5 y^{2} - 90 y - 495 = 0

What is the eccentricity (x^2)/(49)+(y^2)/(25)=1 ?
The eccentricity (x^2)/(49)+(y^2)/(25)=1 is (2sqrt(6))/7