What is the eccentricity ((x-4)^2)/4+(y^2)/(16)=1 ?

The eccentricity ((x-4)^2)/4+(y^2)/(16)=1 is (sqrt(3))/2

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eccentricity ((x-4)^2)/4+(y^2)/(16)=1

eccentricity

\frac{( x - 4 ) ^{2}}{4} + \frac{y ^{2}}{16} = 1

\frac{3}{2}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{( x - 4 ) ^{2}}{4} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (4, 0), b = 4, a = 2

= \frac{4 ^{2} - 2 ^{2}}{4}

\frac{4 ^{2} - 2 ^{2}}{4} = \frac{3}{2}

= \frac{3}{2}

6 x^{2} + 9 y^{2} = 54

10 x^{2} + 35 y^{2} = 5

\frac{x ^{2}}{13.44} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{9 ^{2}} = 1

25 x^{2} + 9 y^{2} - 150 x - 18 y + 9 = 0

What is the eccentricity ((x-4)^2)/4+(y^2)/(16)=1 ?
The eccentricity ((x-4)^2)/4+(y^2)/(16)=1 is (sqrt(3))/2