What is the eccentricity ((x-4)^2)/2+((y-4)^2)/3 =1 ?

The eccentricity ((x-4)^2)/2+((y-4)^2)/3 =1 is 1/(sqrt(3))

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eccentricity ((x-4)^2)/2+((y-4)^2)/3 =1

eccentricity

\frac{1}{3}

Decimal

0.57735 \dots

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{( x - 4 ) ^{2}}{2} + \frac{( y - 4 ) ^{2}}{3} = 1 :

Ellipse with center

(h, k) = (4, 4), b = 3, a = 2

= \frac{( 3 ) ^{2} - ( 2 ) ^{2}}{3}

\frac{( 3 ) ^{2} - ( 2 ) ^{2}}{3} = \frac{1}{3}

= \frac{1}{3}

What is the eccentricity ((x-4)^2)/2+((y-4)^2)/3 =1 ?
The eccentricity ((x-4)^2)/2+((y-4)^2)/3 =1 is 1/(sqrt(3))