What is the eccentricity (x^2)/4+(y^2)/1 =1 ?

The eccentricity (x^2)/4+(y^2)/1 =1 is (sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

eccentricity (x^2)/4+(y^2)/1 =1

eccentricity

\frac{3}{2}

Decimal

0.86602 \dots

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 1

= \frac{2 ^{2} - 1 ^{2}}{2}

\frac{2 ^{2} - 1 ^{2}}{2} = \frac{3}{2}

= \frac{3}{2}

What is the eccentricity (x^2)/4+(y^2)/1 =1 ?
The eccentricity (x^2)/4+(y^2)/1 =1 is (sqrt(3))/2