What is the eccentricity (x^2)/(49)+(y^2)/(16)=1 ?

The eccentricity (x^2)/(49)+(y^2)/(16)=1 is (sqrt(33))/7

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eccentricity (x^2)/(49)+(y^2)/(16)=1

eccentricity

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1

\frac{33}{7}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{49} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 4

= \frac{7 ^{2} - 4 ^{2}}{7}

\frac{7 ^{2} - 4 ^{2}}{7} = \frac{33}{7}

= \frac{33}{7}

x^{2} + 16 y^{2} - 64 = 0

x^{2} + 4 y^{2} - 6 x + 8 y + 9 = 0

2 x^{2} + 7 y^{2} = 14

27 x^{2} + 48 y^{2} - 54 x - 192 y - 213 = 0

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

What is the eccentricity (x^2)/(49)+(y^2)/(16)=1 ?
The eccentricity (x^2)/(49)+(y^2)/(16)=1 is (sqrt(33))/7