What is the eccentricity (x^2)/(16)+(y^2)/(80)=1 ?

The eccentricity (x^2)/(16)+(y^2)/(80)=1 is 2/(sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

eccentricity (x^2)/(16)+(y^2)/(80)=1

eccentricity

\frac{2}{5}

Decimal

0.89442 \dots

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{80} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 45, a = 4

= \frac{( 4 5 ) ^{2} - 4 ^{2}}{4 5}

\frac{( 4 5 ) ^{2} - 4 ^{2}}{4 5} = \frac{2}{5}

= \frac{2}{5}

What is the eccentricity (x^2)/(16)+(y^2)/(80)=1 ?
The eccentricity (x^2)/(16)+(y^2)/(80)=1 is 2/(sqrt(5))