What is the eccentricity 25x^2+9y^2=225 ?

The eccentricity 25x^2+9y^2=225 is 4/5

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eccentricity 25x^2+9y^2=225

eccentricity

25 x^{2} + 9 y^{2} = 225

\frac{4}{5}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

25 x^{2} + 9 y^{2} = 225 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 3

= \frac{5 ^{2} - 3 ^{2}}{5}

\frac{5 ^{2} - 3 ^{2}}{5} = \frac{4}{5}

= \frac{4}{5}

5 x^{2} + 7 y^{2} = 70

5 x^{2} + 10 y^{2} = 50

x^{2} + 4 y^{2} - 2 x - 16 y + 13 = 0

x^{2} = 4 y - 2 y^{2}

\frac{( x - 1 ) ^{2}}{6} + \frac{( y - 3 ) ^{2}}{2} = 1

What is the eccentricity 25x^2+9y^2=225 ?
The eccentricity 25x^2+9y^2=225 is 4/5