What is the eccentricity (x^2)/(16)+(y^2)/(12)=1 ?

The eccentricity (x^2)/(16)+(y^2)/(12)=1 is 1/2

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eccentricity (x^2)/(16)+(y^2)/(12)=1

eccentricity

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

\frac{1}{2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 23

= \frac{4 ^{2} - ( 2 3 ) ^{2}}{4}

\frac{4 ^{2} - ( 2 3 ) ^{2}}{4} = \frac{1}{2}

= \frac{1}{2}

x^{2} + 3 y^{2} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} > 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

9 x^{2} + 25 y^{2} - 36 x - 50 y + 60 = 0

What is the eccentricity (x^2)/(16)+(y^2)/(12)=1 ?
The eccentricity (x^2)/(16)+(y^2)/(12)=1 is 1/2