What is the center 4x^2+9y^2=144 ?

The center 4x^2+9y^2=144 is (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

center 4x^2+9y^2=144

center

(0, 0)

Solution steps

4 x^{2} + 9 y^{2} = 144

Rewrite

4 x^{2} + 9 y^{2} = 144

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 4

And the center is:

(0, 0)