What is the center 20x^2-16y^2-40x128x-556=0 ?

The center 20x^2-16y^2-40x128x-556=0 is (0,0)

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center 20x^2-16y^2-40x128x-556=0

center

(0, 0)

Solution steps

20 x^{2} - 16 y^{2} - 40 x \cdot 128 x - 556 = 0

Rewrite

20 x^{2} - 16 y^{2} - 40 x 128 x - 556 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{139}{5 51} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{139}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{139}{5 51}, b = \frac{139}{2}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = \frac{139}{2}, a = \frac{139}{5 51}

And the center is:

(0, 0)

What is the center 20x^2-16y^2-40x128x-556=0 ?
The center 20x^2-16y^2-40x128x-556=0 is (0,0)