What is the center 135x^2+256y^2-34560=0 ?

The center 135x^2+256y^2-34560=0 is (0,0)

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center 135x^2+256y^2-34560=0

center

(0, 0)

Solution steps

135 x^{2} + 256 y^{2} - 34560 = 0

Rewrite

135 x^{2} + 256 y^{2} - 34560 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 6 ^{2}} + \frac{( y - 0 ) ^{2}}{( 3 15 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 16, b = 315

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 16, b = 315

And the center is:

(0, 0)

What is the center 135x^2+256y^2-34560=0 ?
The center 135x^2+256y^2-34560=0 is (0,0)