What is the center (x^2)/4+(y^2)/3 =1 ?

The center (x^2)/4+(y^2)/3 =1 is (0,0)

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center (x^2)/4+(y^2)/3 =1

center

(0, 0)

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 3

And the center is:

(0, 0)