What is the center (x^2)/(25)+((y+3)^2)/(49)=1 ?

The center (x^2)/(25)+((y+3)^2)/(49)=1 is (0,-3)

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center (x^2)/(25)+((y+3)^2)/(49)=1

center

(0, - 3)

Solution steps

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{( y + 3 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 3), a = 5, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, - 3), b = 7, a = 5

And the center is:

(0, - 3)

What is the center (x^2)/(25)+((y+3)^2)/(49)=1 ?
The center (x^2)/(25)+((y+3)^2)/(49)=1 is (0,-3)