What is the foci ((x-7)^2)/(144)+((y-4)^2)/(128)=1 ?

The foci ((x-7)^2)/(144)+((y-4)^2)/(128)=1 is (11,4),(3,4)

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foci ((x-7)^2)/(144)+((y-4)^2)/(128)=1

foci

(11, 4), (3, 4)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x - 7 ) ^{2}}{144} + \frac{( y - 4 ) ^{2}}{128} = 1 :

Ellipse with center

(h, k) = (7, 4), a = 12, b = 82

(7 + c, 4), (7 - c, 4)

Compute

c :

c = 1 2^{2} - (82)^{2} : 4

(7 + 4, 4), (7 - 4, 4)

Refine

(11, 4), (3, 4)

What is the foci ((x-7)^2)/(144)+((y-4)^2)/(128)=1 ?
The foci ((x-7)^2)/(144)+((y-4)^2)/(128)=1 is (11,4),(3,4)