2x-3y^2=-1

Lösung

2 x - 3 y^{2} = - 1

(h, k) = (- \frac{1}{2}, 0), p = \frac{1}{6}

Schritte zur Lösung

2 x - 3 y^{2} = - 1

Rewrite

2 x - 3 y^{2} = - 1

in the standard form:

4 \cdot \frac{1}{6} (x - (- \frac{1}{2})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, 0), p = \frac{1}{6}