What is the foci 25x^2+144y^2=900 ?

The foci 25x^2+144y^2=900 is ((sqrt(119))/2 ,0),(-(sqrt(119))/2 ,0)

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foci 25x^2+144y^2=900

foci

(\frac{119}{2}, 0), (- \frac{119}{2}, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

25 x^{2} + 144 y^{2} = 900 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = \frac{5}{2}

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} - (\frac{5}{2})^{2} : \frac{119}{2}

(0 + \frac{119}{2}, 0), (0 - \frac{119}{2}, 0)

Refine

(\frac{119}{2}, 0), (- \frac{119}{2}, 0)

What is the foci 25x^2+144y^2=900 ?
The foci 25x^2+144y^2=900 is ((sqrt(119))/2 ,0),(-(sqrt(119))/2 ,0)