What is the foci 3x^2+y^2-24x+39=0 ?

The foci 3x^2+y^2-24x+39=0 is (4,sqrt(6)),(4,-sqrt(6))

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foci 3x^2+y^2-24x+39=0

foci

(4, 6), (4, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

3 x^{2} + y^{2} - 24 x + 39 = 0 :

Ellipse with center

(h, k) = (4, 0), b = 3, a = 3

(4, 0 + c), (4, 0 - c)

Compute

c :

c = 3^{2} - 3^{2} : 6

(4, 0 + 6), (4, 0 - 6)

Refine

(4, 6), (4, - 6)

What is the foci 3x^2+y^2-24x+39=0 ?
The foci 3x^2+y^2-24x+39=0 is (4,sqrt(6)),(4,-sqrt(6))