What is the vertices ((x+4)^2)/5+((y-6)^2)/9 =1 ?

The vertices ((x+4)^2)/5+((y-6)^2)/9 =1 is (-4,9),(-4,3)

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vertices ((x+4)^2)/5+((y-6)^2)/9 =1

vertices

(- 4, 9), (- 4, 3)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{( x + 4 ) ^{2}}{5} + \frac{( y - 6 ) ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (- 4, 6), b = 3, a = 5

(- 4, 6 + 3), (- 4, 6 - 3)

Refine

(- 4, 9), (- 4, 3)

What is the vertices ((x+4)^2)/5+((y-6)^2)/9 =1 ?
The vertices ((x+4)^2)/5+((y-6)^2)/9 =1 is (-4,9),(-4,3)