What is x^2+3x+2m(x)-1=0 ?

The solution to x^2+3x+2m(x)-1=0 is Parabola with (h,k)=(-3/2 , 13/8),p=-1/2

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x^2+3x+2m(x)-1=0

x^{2} + 3 x + 2 m (x) - 1 = 0

(h, k) = (- \frac{3}{2}, \frac{13}{8}), p = - \frac{1}{2}

Solution steps

x^{2} + 3 x + 2 y - 1 = 0

Rewrite

x^{2} + 3 x + 2 y - 1 = 0

in the standard form

4 (- \frac{1}{2}) (y - \frac{13}{8}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{13}{8}), p = - \frac{1}{2}

yy - 3 x = 13

x = z^{2}

(x - 3)^{2} = 8 (y + 1)

4 y^{2} + 8 x = 0

y^{2} - y - x + 6 = 0

What is x^2+3x+2m(x)-1=0 ?
The solution to x^2+3x+2m(x)-1=0 is Parabola with (h,k)=(-3/2 , 13/8),p=-1/2