What is the vertices 9x^2+y^2=84 ?

The vertices 9x^2+y^2=84 is (0,2sqrt(21)),(0,-2sqrt(21))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices 9x^2+y^2=84

vertices

9 x^{2} + y^{2} = 84

(0, 221), (0, - 221)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + y^{2} = 84 :

Ellipse with center

(h, k) = (0, 0), b = 221, a = \frac{2 7}{3}

(0, 0 + 221), (0, 0 - 221)

Refine

(0, 221), (0, - 221)

\frac{( x - 4 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0

3 x^{2} + 7 y^{2} = 63

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{2} + \frac{y ^{2}}{4} = 1

What is the vertices 9x^2+y^2=84 ?
The vertices 9x^2+y^2=84 is (0,2sqrt(21)),(0,-2sqrt(21))