What is the vertices 9x^2+4y^2-18x+16y-11=0 ?

The vertices 9x^2+4y^2-18x+16y-11=0 is (1,1),(1,-5)

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vertices 9x^2+4y^2-18x+16y-11=0

vertices

9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0

(1, 1), (1, - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0 :

Ellipse with center

(h, k) = (1, - 2), b = 3, a = 2

(1, - 2 + 3), (1, - 2 - 3)

Refine

(1, 1), (1, - 5)

3 x^{2} + 7 y^{2} = 63

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{2} + \frac{y ^{2}}{4} = 1

x^{2} + 2 y^{2} = 3

25 x^{2} + 4 y^{2} - 50 x + 40 y + 25 = 0

What is the vertices 9x^2+4y^2-18x+16y-11=0 ?
The vertices 9x^2+4y^2-18x+16y-11=0 is (1,1),(1,-5)