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Popular >

vertices 5x^2+2y^2=50

Solution

vertices

5 x^{2} + 2 y^{2} = 50

Solution

(0, 5), (0, - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

5 x^{2} + 2 y^{2} = 50 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 10

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

Popular Examples

vertices (x^2)/(63500)+(y^2)/(50900)=1 vertices

\frac{x ^{2}}{63500} + \frac{y ^{2}}{50900} = 1

vertices 3x^2+y^2=84 vertices

3 x^{2} + y^{2} = 84

vertices 25x^2+y^2-100x+8y+91=0 vertices

25 x^{2} + y^{2} - 100 x + 8 y + 91 = 0

vertices 9x^2+4y^2+72x-40y+208=0 vertices

9 x^{2} + 4 y^{2} + 72 x - 40 y + 208 = 0

vertices ((x+2)^2)/9+((y-1)^2)/(25)=1 vertices

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

Frequently Asked Questions (FAQ)

What is the vertices 5x^2+2y^2=50 ?
The vertices 5x^2+2y^2=50 is (0,5),(0,-5)