What is the vertices 9x^2+25y^2=225 ?

The vertices 9x^2+25y^2=225 is (5,0),(-5,0)

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vertices 9x^2+25y^2=225

vertices

9 x^{2} + 25 y^{2} = 225

(5, 0), (- 5, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} = 225 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 3

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

81 x^{2} - 1296 x + 16 y^{2} + 64 y = - 3952

6 x^{2} + 8 y^{2} + 12 x - 32 y = 178

49 x^{2} + 25 y^{2} - 196 x + 250 y - 404 = 0

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 5 ) ^{2}}{25} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

What is the vertices 9x^2+25y^2=225 ?
The vertices 9x^2+25y^2=225 is (5,0),(-5,0)