What is (x^2}{25}+\frac{(y-2)^2)/4 =1 ?

The solution to (x^2}{25}+\frac{(y-2)^2)/4 =1 is Ellipse with (h,k)=(0,2),a=5,b=2

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(x^2}{25}+\frac{(y-2)^2)/4 =1

\frac{x ^{2}}{25} + \frac{( y - 2 ) ^{2}}{4} = 1

(h, k) = (0, 2), a = 5, b = 2

Solution steps

\frac{x ^{2}}{25} + \frac{( y - 2 ) ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{( y - 2 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 2), a = 5, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 2), a = 5, b = 2

y - 3 = - \frac{x}{4 y} (x - 12)

4 x^{2} - 34 y + 13 y^{2} - 36 = 0

5 x^{2} + 2 y^{2} + 12 y = - 8

\frac{( x + 7 ) ^{2}}{16} + \frac{( y + 5 ) ^{2}}{4} = 1

x^{2} + 3 \cdot y^{2} = 84

What is (x^2}{25}+\frac{(y-2)^2)/4 =1 ?
The solution to (x^2}{25}+\frac{(y-2)^2)/4 =1 is Ellipse with (h,k)=(0,2),a=5,b=2