What is 4x^2+y^2-16x-2y+1=0 ?

The solution to 4x^2+y^2-16x-2y+1=0 is Ellipse with (h,k)=(2,1),a=2,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

4x^2+y^2-16x-2y+1=0

4 x^{2} + y^{2} - 16 x - 2 y + 1 = 0

(h, k) = (2, 1), a = 2, b = 4

Solution steps

4 x^{2} + y^{2} - 16 x - 2 y + 1 = 0

Rewrite

4 x^{2} + y^{2} - 16 x - 2 y + 1 = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - 1 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 1), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 1), b = 4, a = 2

What is 4x^2+y^2-16x-2y+1=0 ?
The solution to 4x^2+y^2-16x-2y+1=0 is Ellipse with (h,k)=(2,1),a=2,b=4