What is (x^2)/9+y^2>9 ?

The solution to (x^2)/9+y^2>9 is Ellipse with (h,k)=(0,0),a=9,b=3

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(x^2)/9+y^2>9

\frac{x ^{2}}{9} + y^{2} > 9

(h, k) = (0, 0), a = 9, b = 3

Solution steps

\frac{x ^{2}}{9} + y^{2} > 9

Rewrite

\frac{x ^{2}}{9} + y^{2} > 9

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{9 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 9, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 9, b = 3

\frac{( x + 8 ) ^{2}}{20} + \frac{( y + 36 ) ^{2}}{36} = 1

4 x^{2} + y^{2} - 16 x - 2 y + 1 = 0

5 x^{2} + z^{2} = 100

\frac{( x + 2 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{36} = 1

\frac{25 x ^{2}}{400 - 1 2 ^{2}} + \frac{16 y ^{2}}{400 - 1 2 ^{2}} = 1

What is (x^2)/9+y^2>9 ?
The solution to (x^2)/9+y^2>9 is Ellipse with (h,k)=(0,0),a=9,b=3