What is ((x+11)^2)/(100)+((y-4)^2)/(19^2)=1 ?

The solution to ((x+11)^2)/(100)+((y-4)^2)/(19^2)=1 is Ellipse with (h,k)=(-11,4),a=10,b=19

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((x+11)^2)/(100)+((y-4)^2)/(19^2)=1

\frac{( x + 11 ) ^{2}}{100} + \frac{( y - 4 ) ^{2}}{1 9 ^{2}} = 1

(h, k) = (- 11, 4), a = 10, b = 19

Solution steps

\frac{( x + 11 ) ^{2}}{100} + \frac{( y - 4 ) ^{2}}{1 9 ^{2}} = 1

Rewrite

\frac{( x + 11 ) ^{2}}{100} + \frac{( y - 4 ) ^{2}}{1 9 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 11 ) ) ^{2}}{1 0 ^{2}} + \frac{( y - 4 ) ^{2}}{1 9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 11, 4), a = 10, b = 19

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 11, 4), b = 19, a = 10

What is ((x+11)^2)/(100)+((y-4)^2)/(19^2)=1 ?
The solution to ((x+11)^2)/(100)+((y-4)^2)/(19^2)=1 is Ellipse with (h,k)=(-11,4),a=10,b=19