(y^2)/(16)+(x^2)/(36)=1

Lösung

\frac{y ^{2}}{16} + \frac{x ^{2}}{36} = 1

(h, k) = (0, 0), a = 6, b = 4

Schritte zur Lösung

\frac{y ^{2}}{16} + \frac{x ^{2}}{36} = 1

Rewrite

\frac{y ^{2}}{16} + \frac{x ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 4

\frac{( x + 2 ) ^{2}}{55} + \frac{( y - 2 ) ^{2}}{64} = 1

\frac{( x + 4 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{4} = 1

- 8 x^{2} - y^{2} - 4 x + 5 y + 9 = 0

(\frac{X}{3})^{2} + (\frac{Y}{2})^{2} = 1

x^{2} + 14 (y - \frac{13}{14})^{2} - \frac{125}{14} = 0