What is 1-x^2-(y^2)/4 >= 0 ?

The solution to 1-x^2-(y^2)/4 >= 0 is Ellipse with (h,k)=(0,0),a=1,b=2

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1-x^2-(y^2)/4 >= 0

1 - x^{2} - \frac{y ^{2}}{4} \geq 0

(h, k) = (0, 0), a = 1, b = 2

Solution steps

1 - x^{2} - \frac{y ^{2}}{4} \geq 0

Rewrite

1 - x^{2} - \frac{y ^{2}}{4} \geq 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 1

x, (x - k (x)^{2}) = k (x)^{2} + 2 x + x^{2}

7 x + 14 y - 8 x^{2} - 8 y^{2} = 15

- 4 x^{2} - 9 y^{2} - 16 x - 54 y - 101 = 0

\frac{( x - 5 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{4} = 1

\frac{y ^{2}}{16} + \frac{x ^{2}}{36} = 1

What is 1-x^2-(y^2)/4 >= 0 ?
The solution to 1-x^2-(y^2)/4 >= 0 is Ellipse with (h,k)=(0,0),a=1,b=2