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Popular >

5x^2+9y^2-10x-36y=4

Solution

5 x^{2} + 9 y^{2} - 10 x - 36 y = 4

Solution

(h, k) = (1, 2), a = 3, b = 5

Solution steps

5 x^{2} + 9 y^{2} - 10 x - 36 y = 4

Rewrite

5 x^{2} + 9 y^{2} - 10 x - 36 y = 4

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} + \frac{( y - 2 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 2), a = 3, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 2), a = 3, b = 5

Popular Examples

((x^2}{16})+(\frac{y^2)/4)=1

(\frac{x ^{2}}{16}) + (\frac{y ^{2}}{4}) = 1

((x+2)^2)/(15)+(y^2)/(64)=1

\frac{( x + 2 ) ^{2}}{15} + \frac{y ^{2}}{64} = 1

(x^2+8x)+(3y^2+8y)=11

(x^{2} + 8 x) + (3 y^{2} + 8 y) = 11

((x+2)^2}{20}+\frac{(y-3)^2)/4 =1

\frac{( x + 2 ) ^{2}}{20} + \frac{( y - 3 ) ^{2}}{4} = 1

-4x^2-9y^2+8x-18y+23=0

- 4 x^{2} - 9 y^{2} + 8 x - 18 y + 23 = 0

Frequently Asked Questions (FAQ)

What is 5x^2+9y^2-10x-36y=4 ?
The solution to 5x^2+9y^2-10x-36y=4 is Ellipse with (h,k)=(1,2),a=3,b=sqrt(5)