What is (x^2)/(64)+((y-6)^2)/(121)=1 ?

The solution to (x^2)/(64)+((y-6)^2)/(121)=1 is Ellipse with (h,k)=(0,6),a=8,b=11

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(x^2)/(64)+((y-6)^2)/(121)=1

\frac{x ^{2}}{64} + \frac{( y - 6 ) ^{2}}{121} = 1

(h, k) = (0, 6), a = 8, b = 11

Solution steps

\frac{x ^{2}}{64} + \frac{( y - 6 ) ^{2}}{121} = 1

Rewrite

\frac{x ^{2}}{64} + \frac{( y - 6 ) ^{2}}{121} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 6 ) ^{2}}{1 1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 6), a = 8, b = 11

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 6), b = 11, a = 8

4 x^{(2)} + y^{(2)} = 2 y

\frac{x ^{2}}{49} + \frac{y ^{2}}{40} = 1

3 = \frac{x ^{2}}{4} + \frac{y ^{2}}{9}

\frac{( x - 3 ) ^{2}}{49} + \frac{( y - 5 ) ^{2}}{16} = 1

\frac{x ^{2}}{64} + \frac{( y - 3 ) ^{2}}{9} = 1

What is (x^2)/(64)+((y-6)^2)/(121)=1 ?
The solution to (x^2)/(64)+((y-6)^2)/(121)=1 is Ellipse with (h,k)=(0,6),a=8,b=11