What is 4x^2+7y^2=8 ?

The solution to 4x^2+7y^2=8 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=(2sqrt(2))/(sqrt(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

4x^2+7y^2=8

4 x^{2} + 7 y^{2} = 8

(h, k) = (0, 0), a = 2, b = \frac{2 2}{7}

Solution steps

4 x^{2} + 7 y^{2} = 8

Rewrite

4 x^{2} + 7 y^{2} = 8

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{2 2}{7} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = \frac{2 2}{7}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = \frac{2 2}{7}

What is 4x^2+7y^2=8 ?
The solution to 4x^2+7y^2=8 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=(2sqrt(2))/(sqrt(7))