What is 8x^{(2)}+2y^{(2)}+16x=0 ?

The solution to 8x^{(2)}+2y^{(2)}+16x=0 is Ellipse with (h,k)=(-1,0),a=1,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8x^{(2)}+2y^{(2)}+16x=0

8 x^{(2)} + 2 y^{(2)} + 16 x = 0

(h, k) = (- 1, 0), a = 1, b = 2

Solution steps

8 x^{2} + 2 y^{2} + 16 x = 0

Rewrite

8 x^{2} + 2 y^{2} + 16 x = 0

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 0), b = 2, a = 1

2 x^{2} + 5 y^{2} + 3 x + 30 y - 16 = 0

8 x^{2} + y^{2} = 10

4 x^{2} + 7 y^{2} = 8

\frac{( x - 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{9} = 1

49 x^{2} + 64 y^{2} = 25

What is 8x^{(2)}+2y^{(2)}+16x=0 ?
The solution to 8x^{(2)}+2y^{(2)}+16x=0 is Ellipse with (h,k)=(-1,0),a=1,b=2