((x-23)^2)/(841)+((y+28)^2)/(484)=1

Lösung

\frac{( x - 23 ) ^{2}}{841} + \frac{( y + 28 ) ^{2}}{484} = 1

(h, k) = (23, - 28), a = 29, b = 22

Schritte zur Lösung

\frac{( x - 23 ) ^{2}}{841} + \frac{( y + 28 ) ^{2}}{484} = 1

Rewrite

\frac{( x - 23 ) ^{2}}{841} + \frac{( y + 28 ) ^{2}}{484} = 1

in the form of the standard ellipse equation

\frac{( x - 23 ) ^{2}}{2 9 ^{2}} + \frac{( y - ( - 28 ) ) ^{2}}{2 2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (23, - 28), a = 29, b = 22

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (23, - 28), a = 29, b = 22

3 x^{2} - 12 x + 2 y^{2} + 8 y + 14 = 0

(x - 7)^{2} + 6 y^{2} + 12 y = 0

(\frac{x + 2}{4})^{2} + (\frac{y - 3}{16})^{2} = 1

4 x^{2} + 9 y^{2} = 2 x

x^{2} + 4 x + 4 y^{2} = 0