What is (x^2)/4+(1-y/2)^2=1 ?

The solution to (x^2)/4+(1-y/2)^2=1 is Ellipse with (h,k)=(0,2),a=2,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(x^2)/4+(1-y/2)^2=1

\frac{x ^{2}}{4} + (1 - \frac{y}{2})^{2} = 1

(h, k) = (0, 2), a = 2, b = 2

Solution steps

\frac{x ^{2}}{4} + (1 - \frac{y}{2})^{2} = 1

Rewrite

\frac{x ^{2}}{4} + (1 - \frac{y}{2})^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 2), a = 2, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 2), b = 2, a = 2

What is (x^2)/4+(1-y/2)^2=1 ?
The solution to (x^2)/4+(1-y/2)^2=1 is Ellipse with (h,k)=(0,2),a=2,b=2