What is (x^2)/(36)+((y+9)^2)/(81)=1 ?

The solution to (x^2)/(36)+((y+9)^2)/(81)=1 is Ellipse with (h,k)=(0,-9),a=6,b=9

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(x^2)/(36)+((y+9)^2)/(81)=1

\frac{x ^{2}}{36} + \frac{( y + 9 ) ^{2}}{81} = 1

(h, k) = (0, - 9), a = 6, b = 9

Solution steps

\frac{x ^{2}}{36} + \frac{( y + 9 ) ^{2}}{81} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{( y + 9 ) ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - ( - 9 ) ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 9), a = 6, b = 9

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, - 9), b = 9, a = 6

4 x^{2} + 18 y^{2} = 36

(x - 3)^{2} + \frac{( y + 1 ) ^{2}}{49} = 1

22 y^{2} + 32 x^{2} - 308 y - 512 x + 2.422 = 0

- 3 y^{2} - 3 x^{2} + 5 x + 10 y = 5 x^{2} + 1

\frac{x}{( x ^{2} + y ^{2} )} = - 1

What is (x^2)/(36)+((y+9)^2)/(81)=1 ?
The solution to (x^2)/(36)+((y+9)^2)/(81)=1 is Ellipse with (h,k)=(0,-9),a=6,b=9