What is ((x+7)^2)/(144)+((y+2)^2)/(100)=1 ?

The solution to ((x+7)^2)/(144)+((y+2)^2)/(100)=1 is Ellipse with (h,k)=(-7,-2),a=12,b=10

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((x+7)^2)/(144)+((y+2)^2)/(100)=1

\frac{( x + 7 ) ^{2}}{144} + \frac{( y + 2 ) ^{2}}{100} = 1

(h, k) = (- 7, - 2), a = 12, b = 10

Solution steps

\frac{( x + 7 ) ^{2}}{144} + \frac{( y + 2 ) ^{2}}{100} = 1

Rewrite

\frac{( x + 7 ) ^{2}}{144} + \frac{( y + 2 ) ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 7 ) ) ^{2}}{1 2 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 7, - 2), a = 12, b = 10

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 7, - 2), a = 12, b = 10

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22 y^{2} + 32 x^{2} - 308 y - 512 x + 2.422 = 0

- 3 y^{2} - 3 x^{2} + 5 x + 10 y = 5 x^{2} + 1

What is ((x+7)^2)/(144)+((y+2)^2)/(100)=1 ?
The solution to ((x+7)^2)/(144)+((y+2)^2)/(100)=1 is Ellipse with (h,k)=(-7,-2),a=12,b=10