What is ((x-9)^2)/(64)+((y+2)^2)/(25)=1 ?

The solution to ((x-9)^2)/(64)+((y+2)^2)/(25)=1 is Ellipse with (h,k)=(9,-2),a=8,b=5

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((x-9)^2)/(64)+((y+2)^2)/(25)=1

\frac{( x - 9 ) ^{2}}{64} + \frac{( y + 2 ) ^{2}}{25} = 1

(h, k) = (9, - 2), a = 8, b = 5

Solution steps

\frac{( x - 9 ) ^{2}}{64} + \frac{( y + 2 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 9 ) ^{2}}{64} + \frac{( y + 2 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 9 ) ^{2}}{8 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (9, - 2), a = 8, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (9, - 2), a = 8, b = 5

What is ((x-9)^2)/(64)+((y+2)^2)/(25)=1 ?
The solution to ((x-9)^2)/(64)+((y+2)^2)/(25)=1 is Ellipse with (h,k)=(9,-2),a=8,b=5