What is ((y-4)^2)/9+((x-1)^2)/4 =1 ?

The solution to ((y-4)^2)/9+((x-1)^2)/4 =1 is Ellipse with (h,k)=(1,4),a=2,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

((y-4)^2)/9+((x-1)^2)/4 =1

\frac{( y - 4 ) ^{2}}{9} + \frac{( x - 1 ) ^{2}}{4} = 1

(h, k) = (1, 4), a = 2, b = 3

Solution steps

\frac{( y - 4 ) ^{2}}{9} + \frac{( x - 1 ) ^{2}}{4} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{9} + \frac{( x - 1 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} + \frac{( y - 4 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 4), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 4), b = 3, a = 2

What is ((y-4)^2)/9+((x-1)^2)/4 =1 ?
The solution to ((y-4)^2)/9+((x-1)^2)/4 =1 is Ellipse with (h,k)=(1,4),a=2,b=3