What is 9x^2+25y^2=400 ?

The solution to 9x^2+25y^2=400 is Ellipse with (h,k)=(0,0),a= 20/3 ,b=4

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9x^2+25y^2=400

9 x^{2} + 25 y^{2} = 400

(h, k) = (0, 0), a = \frac{20}{3}, b = 4

Solution steps

9 x^{2} + 25 y^{2} = 400

Rewrite

9 x^{2} + 25 y^{2} = 400

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{20}{3} ) ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{20}{3}, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{20}{3}, b = 4

What is 9x^2+25y^2=400 ?
The solution to 9x^2+25y^2=400 is Ellipse with (h,k)=(0,0),a= 20/3 ,b=4