What is ((x^2)/(64))+((y^2)/(36))=1 ?

The solution to ((x^2)/(64))+((y^2)/(36))=1 is Ellipse with (h,k)=(0,0),a=8,b=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

((x^2)/(64))+((y^2)/(36))=1

(\frac{x ^{2}}{64}) + (\frac{y ^{2}}{36}) = 1

(h, k) = (0, 0), a = 8, b = 6

Solution steps

\frac{x ^{2}}{64} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{64} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 8, b = 6

What is ((x^2)/(64))+((y^2)/(36))=1 ?
The solution to ((x^2)/(64))+((y^2)/(36))=1 is Ellipse with (h,k)=(0,0),a=8,b=6