What is -1=(((x-0))/(1^2))^2+(((y-1))/(1^2))^2 ?

The solution to -1=(((x-0))/(1^2))^2+(((y-1))/(1^2))^2 is Ellipse with (h,k)=(0,1),a=1,b=1

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-1=(((x-0))/(1^2))^2+(((y-1))/(1^2))^2

- 1 = (\frac{( x - 0 )}{1 ^{2}})^{2} + (\frac{( y - 1 )}{1 ^{2}})^{2}

(h, k) = (0, 1), a = 1, b = 1

Solution steps

- 1 = (\frac{x - 0}{1 ^{2}})^{2} + (\frac{y - 1}{1 ^{2}})^{2}

Rewrite

- 1 - (\frac{x - 0}{1 ^{2}})^{2} - (\frac{y - 1}{1 ^{2}})^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 1), a = 1, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 1), b = 1, a = 1

What is -1=(((x-0))/(1^2))^2+(((y-1))/(1^2))^2 ?
The solution to -1=(((x-0))/(1^2))^2+(((y-1))/(1^2))^2 is Ellipse with (h,k)=(0,1),a=1,b=1