What is (((x+1)^2))/3+(((y+1)^2))/4 =1 ?

The solution to (((x+1)^2))/3+(((y+1)^2))/4 =1 is Ellipse with (h,k)=(-1,-1),a=sqrt(3),b=2

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(((x+1)^2))/3+(((y+1)^2))/4 =1

\frac{( ( x + 1 ) ^{2} )}{3} + \frac{( ( y + 1 ) ^{2} )}{4} = 1

(h, k) = (- 1, - 1), a = 3, b = 2

Solution steps

\frac{( x + 1 ) ^{2}}{3} + \frac{( y + 1 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{3} + \frac{( y + 1 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{( 3 ) ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 1), a = 3, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 1), b = 2, a = 3

What is (((x+1)^2))/3+(((y+1)^2))/4 =1 ?
The solution to (((x+1)^2))/3+(((y+1)^2))/4 =1 is Ellipse with (h,k)=(-1,-1),a=sqrt(3),b=2