What is ((x-4)^2)/(25)+((y+7)^2)/(16)=1 ?

The solution to ((x-4)^2)/(25)+((y+7)^2)/(16)=1 is Ellipse with (h,k)=(4,-7),a=5,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

((x-4)^2)/(25)+((y+7)^2)/(16)=1

\frac{( x - 4 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{16} = 1

(h, k) = (4, - 7), a = 5, b = 4

Solution steps

\frac{( x - 4 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 4 ) ^{2}}{5 ^{2}} + \frac{( y - ( - 7 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (4, - 7), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (4, - 7), a = 5, b = 4

What is ((x-4)^2)/(25)+((y+7)^2)/(16)=1 ?
The solution to ((x-4)^2)/(25)+((y+7)^2)/(16)=1 is Ellipse with (h,k)=(4,-7),a=5,b=4