What is (y^2)/4+z^2=1 ?

The solution to (y^2)/4+z^2=1 is Ellipse with (h,k)=(0,0),a=2,b=1

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(y^2)/4+z^2=1

\frac{y ^{2}}{4} + z^{2} = 1

(h, k) = (0, 0), a = 2, b = 1

Solution steps

\frac{y ^{2}}{4} + z^{2} = 1

Rewrite

\frac{y ^{2}}{4} + z^{2} = 1

in the form of the standard ellipse equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} + \frac{( z - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

What is (y^2)/4+z^2=1 ?
The solution to (y^2)/4+z^2=1 is Ellipse with (h,k)=(0,0),a=2,b=1