What is 9x^2+16y^2+72x=0 ?

The solution to 9x^2+16y^2+72x=0 is Ellipse with (h,k)=(-4,0),a=4,b=3

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9x^2+16y^2+72x=0

9 x^{2} + 16 y^{2} + 72 x = 0

(h, k) = (- 4, 0), a = 4, b = 3

Solution steps

9 x^{2} + 16 y^{2} + 72 x = 0

Rewrite

9 x^{2} + 16 y^{2} + 72 x = 0

in the form of the standard ellipse equation

\frac{( x - ( - 4 ) ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 4, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 4, 0), a = 4, b = 3

What is 9x^2+16y^2+72x=0 ?
The solution to 9x^2+16y^2+72x=0 is Ellipse with (h,k)=(-4,0),a=4,b=3