What is ((x-2)^2)/9+((y+1)^2)/(36)=1 ?

The solution to ((x-2)^2)/9+((y+1)^2)/(36)=1 is Ellipse with (h,k)=(2,-1),a=3,b=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

((x-2)^2)/9+((y+1)^2)/(36)=1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{36} = 1

(h, k) = (2, - 1), a = 3, b = 6

Solution steps

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 1), a = 3, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, - 1), b = 6, a = 3

What is ((x-2)^2)/9+((y+1)^2)/(36)=1 ?
The solution to ((x-2)^2)/9+((y+1)^2)/(36)=1 is Ellipse with (h,k)=(2,-1),a=3,b=6