What is 2y-x^2-y^2>0 ?

The solution to 2y-x^2-y^2>0 is Ellipse with (h,k)=(0,1),a=1,b=1

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2y-x^2-y^2>0

2 y - x^{2} - y^{2} > 0

(h, k) = (0, 1), a = 1, b = 1

Solution steps

2 y - x^{2} - y^{2} > 0

Rewrite

2 y - x^{2} - y^{2} > 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 1), a = 1, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 1), b = 1, a = 1

What is 2y-x^2-y^2>0 ?
The solution to 2y-x^2-y^2>0 is Ellipse with (h,k)=(0,1),a=1,b=1